Fill in a base 6 multiplication table. and use the table and the standard algorithm to solve.

See in bold

1 x 1 = 1

1 x 2 = 2

1 x 3 = 2

1 x 4 = 4

1 x 5 = 5

2 x 1  = 2

2 x 2 = 4

2 x 3 = 6

2 x 4 = 8

2 x 5 = 10

3 x 1 = 3

3 x 2 = 6

3 x 3 = 9

3 x 4 = 12     Total 70

3 x 5 = 15

4 x 1 = 4

4 x 2 = 8

4 x 3 = 12

4 x 4 = 16   total 125

4 x 5 = 20

5 x 1 = 5

5 x 2  = 10

5 x 3  = 15  total 175

5 x 4 = 20

5 x 5 = 25  total 220

Total = 220

Algorithm Finding 142  =  220  - 78  = 142

-78 = 6 x 13 therefore 142six = 13

Algarithm Finding X 230six = X diagonal

X diagonal list on table shows;

1 x 1 = 1

2 x2 = 4

3 x 3 = 9

4 x 4 = 16

5 x 5 = 25

6 x 6 = 36

Total = 91

230/91 = 2.52747253  if diagonal algorithm

or 230 taken from the last 5 x 5 algorithm total = 220

1 x 6 = 6   220 + 6 = 226   x = 4+  then 1 x 6

2 x 6 = 12  = 18    220 + 18 = 38  x = 8 - then 2 x 6

as X230 = 8- 230 = 2 x 6

or X230 = 4+ 230 = 1 x 6  

i will pick c put check it over to be sure

step-by-step explanation: