Mathematics, 21.06.2021 22:30 trillralyn4060
Use a double integral to find the area of the following regions. The region bounded by all leaves of the rose r=2cos3θ
Answers: 3
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![Area = 3\int_{-\frac{\pi }{6}}^{\frac{\pi }{6}}\frac{r^{2}}{2}d\Theta \\\\ = \frac{3}{2}\int_{-\frac{\pi }{6}}^{\frac{\pi }{6}}4 cos^{2}\left ( 3\Theta \right ) d\Theta \\\\ = \frac{12}{2}\int_{-\frac{\pi }{6}}^{\frac{\pi }{6}} \frac{cos(6\Theta +1)}{2}d\Theta\\\\ =\frac{6}{2}\left [ \frac{sin(6\Theta +\Theta )}{6} \right ]_{-\frac{\pi }{6}}^{\frac{\pi }{6}}\\\\ =3\times \left [ \frac{\pi }{6}+\frac{\pi }{6} \right ]\\\\ =3\times \frac{2\pi }{6}\\\\ = \pi](/tpl/images/1380/7791/5b15e.png)
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Use a double integral to find the area of the following regions. The region bounded by all leaves of...
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