A box has two balls, one white and one red. We select one ball, put it back in the box, and select a second ball (sampling with replacement). Find the probability of the following events: a. Let F = the event of getting the white ball twice.
b. Let G = the event of getting two balls of different colors.
c. Let H = the event of getting white on the first pick.
d. Are F and G mutually exclusive?
e. Are G and H mutually exclusive?

See explanation

Step-by-step explanation:

Given

Represent the balls with the first letters

Solving (a): P(F) --- White balls twice

The event of F is:

So:

Solving (b): P(G) --- two different colors

The event of G is:

So:

Solving (c): P(H) --- White picked first

The event of H is:

So:

Solving (d): F and G, mutually exclusive?

We have:

Check for common elements

Hence, F and G are mutually exclusive

Solving (e): G and G, mutually exclusive?

We have:

Check for common elements

Hence, F and G are not mutually exclusive

answer: i guess 105 degrees?

step-by-step explanation:

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%