Factorise using suitable identities
x^2 - 2x + 1

(x - 1)^2

Step-by-step explanation:

using middle term break method

x^2 - 2x + 1

here, we need to numbers which gives 1 when multiplied and 2 when add .

=x^2 - (1 + 1)x + 1

=x^2 - x - x + 1

=x(x - 1) -1(x - 1)

=(x -1)(x - 1)

=(x - 1)^2

Step-by-step explanation:

by middle term factorisation method

x^2 -2x + 1

= x^2 -( 1+1)x + 1

= x^2 -x -x + 1

= x(x-1) -1( x -1)

= (x-1)(x-1)

OR

we know above polynomial ( quadratic ) equation is in form

(a - b )^2 = a^2 -2ab + b^2

so it's factories form is

( a- b)( a- b)

me! what did you put for this question?

step-by-step explanation:

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

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