The mean of 5 numbers is 30. The median is 33. What might the numbers be?

198 ans

Let a,b,c,d and e are five numbers

mean = (a +b+ c+ d+e)/5 = 30

⇒ (a +b+ c+ d+e) = 150(1)

now, Let the number excluded be a

then, new mean =  (b+ c+ d+e)/4 = 28

⇒ (b+ c+ d+e)= 112

putting this value in (1),

⇒a + 112 = 150

⇒a = 150 -112 = 38

∴ excluded number = 38

{3 + i, 3 - i, 3, -1}

step-by-step explanation:

answer:   y=2x-3

step-by-step explanation: