A $7,000 principal is invested in two accounts, one earning 1% interest and another earning 5% interest. If the total interest for the year is $202, then how much is invested
in each account?
$
at 1% interest
$
at 5% interest

9514 1404 393

Step-by-step explanation:

For "mixture" problems, I like to let the variable represent the amount of the largest contributor. Here, we can let x represent the amount invested at 5%. Then the amount invested at 1% is (7000-x). The total interest earned is ...

  0.05x +0.01(7000 -x) = 202

  0.04x = 132 . . . . . . . . simplify, subtract 70

  x = 3300

  (7000 -x) = 7000 -3300 = 3700 . . . . at 1%

$3700 was invested at 1% interest.

$3300 was invested at 5% interest.

step-by-step explanation:

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi