Will Mark Brainlest help please​

g(-1 )=-1 and g(2)+g(3)=36

Step-by-step explanation:

If g(x) = x^3+x^2-x-2 find g(-1)

if we find g(-1)

we substitute all the x's in the function with -1

-1^3+-1^2-(-1)-2

-1^3 = -1

-1^2 = 1

-1+1+1-2

(two minuses make a plus)

-1+1 = 0

0+1 = 1

1-2 = -1

if x=-1, g(-1) is -1

g(2)+g(3)

substitute the x's in the function with 2 and 3 and add your results

2^3+2^2-2-2

2^3 = 8, 2^2 = 4

8+4-2-2

8+4= 12, 12-2 = 10, 10-2 = 8

g(2)=8

g(3) now

3^3 + 3^2-3-2

3^3=27, 3^2 = 9

27+9-3-2

27+9=33, 33-3 = 30, 30-2 = 28

g(3) = 28

g(2) (which equals 8) + g(3) (which equals 28) =

8+28 = 36

g(2)+g(3)=36

hi there!

the answer will be d: 2

if you was gonna solve for a, a is a   < -12