Problem 5. When a car brakes suddenly, it may leave a skid mark. Given an initial driving speed (m/s), gravity \inline g ( m/s^2) and friction coefficient \inline \mu (no units), the length of a skid mark (m) is defined by the equation d=f(v, u,g)= v^2/2ug ( please see the attachment)

The coefficient changes depending on how slippery the ground is.
Computer and interpret what it means in the context of this situation.
Compute the length of the skid mark when a car is driving 5 meters per second, the friction coefficient is 0.2 and the gravity is 9.8 \inline m/s^2. Then, use differentials to approximate the change in skid length if the velocity increases to 5.2 meters per second and the constant decreases to 0.1.

Which of the following is a solution of z^6 = 64i? 2(cos105° + isin105°) 2(cos120° + isin120°) 2(cos135° + isin135°) 8(cos15° + isin15°)

Julie multiplies 6.27 by 7 and claims the product is 438.9 .explain without multiplying how you know juliesanswer is not correct.find the correct answer

Anull hypothesis states that the difference between 8 hours of sleep and 3 hours of sleep has no effect on the number of pictures a student will remember during a picture memory interface test (pmit). examining the mit database, an extremely small t-value of 0.1611 is found. this t-value is much smaller than the smallest t-value on the chart for p-value reference. from this information we can: select one: a. accept the null hypothesis because the p-value obtained shows that the difference between the two groups being tested is not statistically significant b. accept the null hypothesis because the p-value obtained was statistically significant c. reject the null hypothesis because of the p-value obtained d. reject the null hypothesis because the data obtained is statistically significant