The width of Field A is 7/12 of its length of 108 m. What is the perimeter of Field B if it has 5/6 of the perimeter of Field A?

(100th answer)

perimeter of field b = 260 m

Step-by-step explanation:

First we have to find what is 7/12 of 108?

Well first we need to know what 1/12 of 108 is. Which means we do 108/12. That equals 9. so if 1/12 of 108 = 9

then 7/12 of 108 is 9*7 which is 63.

The width of field A is 63 plus its length, width again and its length again would be its perimeter or

2l + 2w is its perimeter, where l is length and w is width

108*2+63*2= perimeter

216+126 = ?

342 is the perimeter of field A.

We aren't done though.

We have to find 5/6 of 342.

1/6 of 342 is 342/6

342/6 = 52

1/6 of 342 = 52 meaning 5/6 of 342 is equal to 5*52.

5*52 = 260

the perimeter of field b is 260

.

step-by-step explanation:

figure c

step-by-step explanation:

hope this .