The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day, 378 people entered the park, and the admission fees collected totaled 1,042.00 dollars. How many children and how many adults were admitted?

188 children, 190 adults

Step-by-step explanation:

For this equation, let c be the number of children, and a represent the number of adults.

On this day 378 total people were at the park, so

a + c = 378   eq 1

Each adult pays $4, so the admission fee for ALL adults will be $4 multiplied by the number of adults , a, so 4a

Use the same method for the children, and the total all children paid is 1.50c

From all the children and adults, the total was 1042, so merge the 2 cost variables together.

4a + 1.50c = 1042   eq 2

the 2 equations we will use are

a + c = 378

4a + 1.50c = 1042

From equation 1, subtract c from both sides, and

a = 378 - c     eq 3

Substitute the value of a in eq 3 into equation 2

4a + 1.50c = 1042

4 (378 - c) + 1.50c = 1042

1512 - 4c +1.50 c = 1042 (collect like terms)

1512 - 1042 = 4c -1.50 c

470 = 2.5 c

c = 470 /2.5

c = 188 children

Substitute the value of c into eq 3 to get the value of a

a = 378 -c

a = 378 - 188

a = 190 adults

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