How to solve and answer

D.   (-2, 0) and (3, 0).

Step-by-step explanation:

At the x -intercepts the function = 0, so

(2x + 4)(x - 3) = 0

2x + 4 = 0 and x - 3 = 0

x = -4/2 = -2 and x = 3.

So they are (-2, 0) and (3, 0).

x = 3 or x = -2

Step-by-step explanation:

f(x) = (2x + 4)(x - 3)

y = (2x + 4)(x - 3)

x - intercept occurs when y = 0

0 = (2x + 4)(x - 3)

0 = 2x² - 6x + 4x - 12

2x² - 2x - 12 = 0

(2x² - 2x - 12)/2 = 0/2

x² - x - 6 = 0

From the quadratic formula,

x = (-b +- √(b² - 4ac))/2a

x = (- ( -1 ) +- √(( -1)² - 4( 1 )( -6 )))/2( -1 )

x = (1 +- √(1 - ( -24)))/-2

x = (1 +- √25)/-2

x = (1 +- 5)/-2

x = 3 or x = -2

idk this answer sorry cant on this one.

step-by-step explanation: