Find tan 0, where is the angle shown give an exact value not a decimal approximation plz help due soon !

tanθ =

Step-by-step explanation:

let the unknown side be x , then

Using Pythagoras' identity in the right triangle

x² + 5² = 17²

x² + 25 = 289 ( subtract 25 from both sides )

x² = 225 ( take the square root of both sides )

x = = 15

Then

tanθ = =

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation: