SOMEONE HELP, I HAVENT BEEN PAYING ATTENTION TO CLASS

A=4cm

ok to do this we do the formula

A=PiR^2

A=3.14*4^2

A=3.14*16

A=50.24

and the area of circle B is 4 times the area of a so

50.24*4=200.96

200.96=3.14*X^2

Since  r  is on the right side of the equation, switch the sides so it is on the left side of the equation. 3.14 ⋅ r 2 = 200.96  Divide each term by  3.14  and simplify.

r 2 = 64

r=8

CIRLCE A=50.24

CIRLCE B=8

2.83941151 would be the answer you're looking for! : )