The path of a breaching ocra whale can be modeled by the function k(x) = x^2 - 2x - 8, where x is the time elapsed in seconds under water, and k(x) is the height in ft below the water. Determine HOW LONG is the ocra (killer) whale underwater to the nearest second. MUST BE SOLVED ALGEBRAICALLY!

The time duration of the ocra whale spends under water is 4 seconds

Step-by-step explanation:

The equation that model the path of the ocra whale is presented as follows;

k(x) = x² - 2·x - 8

Where;

x = The time elapsed in seconds under water

k(x) = The height in feet below water

Therefore, the point where the ocra whale enters the water, k(x) = 0

At the point of submerging below the water surface, we have;

k(x) = 0 = x² - 2·x - 8

Factorizing the quadratic equation gives;

0 = x² - 2·x - 8 = (x - 4)·(x + 2)

Therefore, when k(x) = 0, either;

(x - 4) = 0, which gives, x = 4

(x + 2) = 0, which gives, x = -2

Given that 'x' represent the time, the time elapsed while the whale is under water, x = 4 seconds

answer: c i think

step-by-step explanation:

55.44 inches

step-by-step explanation:

part a. assuming a perfectly linear relationship, we can find the slope from the first two data points.

slope = m = (change in rainfall)/(change in years)

= (61.80 -62.33)/(2005 -2004) = -0.53/1 = -0.53

then the point-slope form of the equation of the line can be written as

y = m(x -h) +k . . . . . m = -0.53, (h, k) = (0, 62.33)

y = -0.53x +62.33 . . . x = years after 2004

part b. in 2017, x = 2017 -2004 = 13. then the predicted rainfall is

y = -0.53·13 +62.33 = 55.44 . . inches

the predicted rainfall in 2017 is 55.44 in.