Roll one fair, six-sided die, numbered 1 through 6. Let A be the event you will roll an even number.

P(A) = 1/2

Step-by-step explanation:

The question seems incomplete, I assume that we want to find the probability of event A.

Here we have a fair six-sided dice, so each one of the six numbers has exactly the same probability of being rolled.

Such that the possible outcomes of rolling the dice is:

{1, 2, 3, 4, 5, 6}

Now we define event A as rolling an even number.

The possible outcomes such that the event A is true are the even numbers:

{2, 4, 6}

So we have 3 outcomes out of 6.

Then the probability of rolling an even numbers, is just the quotient between the number of outcomes of even numbers (3) and the total number of outcomes (6).

Then:

P(A) = 3/6 = 1/2 = 0.5

too many. (jk)

31 v bucks

step-by-step explanation:

since you bought 25 on friday and 6 on tuesday, you can just add them up.

25+6=31

check your work.

31-6=25

i hope this !

-yand3r3