A farmer stacked hay bales. The volume of each hay bale is 10 2/3 cubic feet. The farmer stacked eight hay bales on top of one another. What is the total height of 1 hay bale? What is the total height of the 8 stacked hay bales? L=1 1/3ft W=4ft

Given:

Stacked Hay Bales:

L = 1 1/3 feet
W = 4 feet

The volume of each hay bale is equal to 10 2/3 cubic feet
The number of hay bales stacked = 8

To solve for the height, use the volume of the bales and the given length and width of a single bale.

V = l x w x h
10 2/3 cubic feet = 1 1/3 feet * 4 feet * height
height = 2 feet

So, if the height of one bale is 2 feet, then the height of 8 bales stacked is

2 feet * 8 bales = 16 feet

Therefore the height of the stacked hay bales is 16 feet.

The principal, real, root of: 50−−√2=7.071067817.07106781−7.0710678150 is not a perfect square