Whats the angle of J

<J = 59

Step-by-step explanation:

Since this is an isosceles triangle, <J and <H are the same

The sum of the angles in a triangle are 180

62+ <J + <H =180

62+ <J + <J = 180

62 + 2 <J =180

Subtract 62 from each side

2 < J = 180-62

2 < J = 118

Divide by 2

<J =118/2

<J = 59

∠J = 59 °

Step-by-step explanation:

Its two angle is equal so, it is isosceles triangle.

so, ∠J and ∠H are same.

∠J = ∠H .. ( in isosceles triangle two side are equal).

so, ∠J = ∠J

62° + ∠J + ∠ J = 180°

combine like terms

62° + ∠2J = 180°

Subtract 62 from each side

62° - 62° + ∠2J = 180° - 62°

∠2J = 118°

Divide each side by 2

∠2J/2 = 118° / 2

∠J = 59 °

Verification :-

∠J + ∠H + 62° = 180°

59° + 59° + 62° = 180°. .( ∠J =∠H - proved above)

118° + 62° = 180°

180° = 180°

LHS = RHS

a. is correct

answer: can you give the

step-by-step explanation: