Drag an answer to each box to complete this paragraph proof. Given: Triangle ABC

Prove: m∠A=72°

By the , the sum of the angles in a triangle is equal to 180°. Therefore, m∠A+m∠B+m∠C=180°. Using the , (6x)°+90°+(x+6)°=180°. To solve for x, first combine like terms to get 7x + 96 = 180. Using the , 7x = 84. Then, using the division property of equality, x = 12. To find the measure of angle A, use the substitution property to get m∠A=6(12)°. Finally, simplifying the expression gets m∠A=72°.

50

step-by-step explanation:

chiken

step-by-step explanation:

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²

the square root of 16 is 4.

4*4 = 16