Consider the equations: y=|x-1| and y=3x+2
What is the approximate solution of this system of equations?

ans: (-3/2, -5/2), (-1/2, -5/4)

Step-by-step explanation:

here;

y =| x - 1| can be any of form I.e

y = x - 1 say equation••••1

OR

y = -( x - 1) say equation •••2

our next equation is,

y = 3x + 2 say equation ••••3

substituting 'y' from equation 1 and 2 to 3

we got

x - 1 = 3x + 2 -( x - 1) = 3x +2

- 3 = 2x -1 = 4x

hence

x= -3/2 and -1/4

substituting x in equation 3 we got

y = -5/2 and -5/4

OR ,

can be solve by iterative method which is quite long

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

combine all like terms then its just a 2 step equation