Two fair dice are tossed. One die is red and one die is green. Calculate the probability that the sum of the numbers on the two dice is an odd number given that the number that shows on the red die is larger than the number that shows on the green die.

1/4

Step-by-step explanation:

The entire sample space for two fair dice is :

Number of faces^2 = 6² = 36

Number of odd sums given that number on red dice is larger than green dice ;

Using the sample space we can count the number of odd sums where the red dice has a larger value than the green dollar dice = 9

Total sample space = 36

Hence, the probability that the sum of the numbers on the two dice is an odd number given that the number that shows on the red die is larger than the number that shows on the green die will be :

(odd sum) / Sample space

9 / 36

= 1/4

y=mx+b

step-by-step explanation:

m slope

b y-intercept

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.