I need help with this math problem

A) (x + 12) and (x + 9)

Step-by-step explanation:

You need to get x^2 + 21x + 108.

A) (x + 12) (x + 9) = x^2 + 12x + 9x + 108 = x^2 + 21x + 108

B) (x - 12) (x - 9) = x^2 - 9x - 12x + 108 = x^2 -21x + 108

C) (x - 27) (x - 4) = x^2 - 4x - 27x + 108 = x^2 - 31x + 108

D) (x + 27) (x + 4) = x^2 + 27x + 4x + 31 = x^2 + 31x + 31

So, the answer is A).

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