Can anyone share the process please? ​

3x³ + x² + x + 1

= 3x³ - 3x² + 4x² - 4x + 5x - 5 + 6

= 3x²(x - 1) + 4x(x - 1) + 5(x - 1) + 6

= (x - 1)(3x² + 4x + 5) + 6

but 3x³ + x² + x + 1 = (x - 1).Q(x) + R

=> Q(x) = 3x² + 4x + 5

R = 6

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180