2 consecutive postive nos are such that the sum of their squares is 113. Find the 2 numbers

7,8

Step-by-step explanation:

n^2+(n+1)^2=113; this is the information we are provided in the question.

n^2+n^2+2n+1=113 ; just expanding the numbers

2n^2+2n-112=0 ; moving everything to the same side

n^2+n - 56= 0 ; divide everything by two

(n-7)(n+8)=0 : factor the polynomial

so answers for n are: 7 and -8. since the questions asks for positive numbers -8 cannot be correct.

so n=7

n+1 = 8

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation: