DIVIDE 4) 120
4)136
71674
171A
6) 400
2) 684
3366
9450
(20 34 01 BD 60 292.69 m2 ala a
09 109 132 ROU. BED 187 10
(10 ore
W 2013
(1 630 (99' (12 % 62
112% 22 0211 0915021
lea
2415
5) 570
5,565
6)832
91954
617223) 619
09
4746
2) 662
71532
9)279
7)917
1845
3) 304
4)248
-)744
2)482
7847
9639
378
3)486
8688
4)476
2) 148
6)942
6775
8)483
2)726
2 22A
6138
7)798
405
8)456
2) 500
9) 927
3) 969
5)245 4642
4392
486
3) 336
5)800
2)334
7)805
9738
4) 690
2218
8 968
B) 440
0
4) 404
a 그
2)354
4) 632
6)762
9)594
3537
5) 675
7777
6426
2252
MEDE DOE OE OE OE ON
7812
5) 345
3) 750
9)918
6)876
8 888
2) 188
5)530
4452
3)463
8) 752
9)477
2 896
6)612
C ㄷ
5660
3)417
J
8)856 5750
9549 4396 2816
71371
C ㄷ
9)931 8568
१)१११
7287
5)795
9)864 7)861
6)564
​

your answer is 7686549.976547

okay so 15.15 *()5: +5/6

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v