figure H has four sides with vertices at 1, 2 and 2, 3 and 3, 2 and 2, 1 Which series of transformations will not map figure H onto itself? (x + 0, y − 2), reflection over y = 1 (x + 2, y − 0), reflection over x = 3 (x + 3, y + 3), reflection over y = −x + 7 (x − 3, y − 3), reflection over y = −x + 2

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

a=r

d=q

c=p

b=s

hope this !

its 4 because 2 times 2 is 4, if you double the number two you get four