Now check your work by using the GeoGebra geometry tool to repeat parts A through D. Open GeoGebra, and complete each step below. If you need help, follow these instructions for using GeoGebra. You will take a screenshot of your work when you are through, so be sure to clearly label your construction as you work. Plot points A, B, and C, and draw a polygon, ΔABC, through the points.
Draw a line perpendicular to through point B.
Label the intersection of the line perpendicular to through B and point D.
Measure and display the slopes of and .
Display the equations of and in the Algebra margin.
Measure and display the lengths of and .
Calculate and display the area of ΔABC.
Take a screenshot showing the geometric construction and the Algebra margin, save it, and insert the image in the space below.

c. side angle side. u shares the same sides

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function