Please help For f(x) = 3x + 1 and g(x) = x ^ 2 - 6 find (8/f)(x)

9x² + 6x - 5

Step-by-step explanation:

If you mean g(f(x))

g(x) = x² - 6

f(x) = 3x + 1

Then, g(f(x)) = g(3x + 1)

but g(x) = x² - 6

g(3x + 1) = (3x + 1)² - 6 = 9x² + 6x + 1 - 6

= 9x² + 6x - 5

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0

i dont understand the question? ?

step-by-step explanation: