6 liters of a 10% vinegar solution is mixed with x liters of a 35% vinegar solution, the result is a 30% vinegar solution. How many liters of the 35% vinegar solution were mixed?
The mixture required _
liter(s) of the 35% solution

9514 1404 393

  24 liters

Step-by-step explanation:

Let x represent the number of liters of 35% solution required. Then the total quantity of vinegar in the mix is ...

  0.10×6 + 0.35x = 0.30(6+x)

  0.05x = 1.2 . . . . . . . . . . . . . . subtract 0.30x+0.60 from both sides

  x = 24 . . . . . . . . . . . . . . . divide by 0.05

The mixture required 24 liters of the 35% solution.

b and c

step-by-step explanation:

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: