Suppose Duarte is one of the ten cities in the air pollution survey. We found that the number of manufacturing enterprises employing 20 or more workers in Duarte is 200, and the annual mean concentration of sulfur dioxide in Duarte is 18 micrograms per cubic meter. What is the residual for the city of Duarte

Kindly check complete question in the attached picture below.

2.2236

Step-by-step explanation:

From the R output given, we can obtain the linear regression model in the form ;

y = bx + c

Intercept, c = 9.4764

Slope, b = 0.0315

x = number of manufacturing enterprise employing 20 or more workers

y = annual mean concentration of Sulphur dioxide

Hence, The regression equation model as obtained from the R output is :

y = 0.0315x + 9.4764

For the city of Duarte;

x = 200

Actual annual mean concentration of Sulphur dioxide is 18 micrograms per cubic meter.

Residual = Actual value - predicted value

Prediction using the regression equation to obtain the predicted annual mean concentration ;

The predicted y value, when x = 200

y = 0.0315(200) + 9.4764

y = 15.7764

The residual, if actual annual concentration = 18

Y residual = 18 - 15.7764 = 2.2236

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752