QUESTION 3 Given: f(x) = 3(x - 1)2 - 12
and g(x)=2+1
3.1 Calculate the coordinates of the x-intercept and the y-intercept of g.
3.2 calculate the coordinates of the x- intercept and the y- intercept of f​

3.1. g(x)=2x+1

for y-inter x=0

then y=2(0)+1

y=1

for x-inter y=0

then y=2x+1

0=2x+1

-1=2x

x=-1/2

3.2. f(x)= 3(x-1)'2 -12

y-inter x=0

=3(0-1)'2-12

= -9

x-inter y =0

0=3(x-1)(x-1)-12

0=3(x'2-2x+1) -12

0=3x'2 -6x +3 -12

0=3x'2 -6x -9

we devide by 3 since is a common factor

0=x'2-2x -3

0=(x - 3)(x +1)

x=3 or x = -1

what do you need me to answer?

step-by-step explanation: