-2 (x + 3z) + 4x - 3y + 2z​

-2 (x + 3z) + 4x - 3y + 2z​

-2x-6x+4x-3y+2z

2x-4z-3y

hope it helps...

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Step-by-step explanation:

-2(x + 3z) + 4x - 3y +2z

-2x -6z + 4x - 3y + 2z

=2x - 4z - 3y

investment b is an ordinary annuity with $3,909.64 in the account after one year.

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)