Find the sum of the first 31 terms of the following series, to the nearest integer.
5, 14,23,...

4340.

Step-by-step explanation:

14-5 = 9 and 23-14 = 9 so this is an arithmetic series with common difference of 9.

Sum of n terms = (n/2)[2a1 + d(n - 1)]

Here n = 31, d = 9 and a1 = 5.

So, substituting, we have:

Sum of 31 terms = (31/2)[2*5 + 9(31-1)]

= 15.5 * 280

= 4340.

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

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