Find the zeros of f(x) = (x -3)^2 - 49 graphically

Step-by-step explanation:

First let fully expand this equation

Use the product of squares method.

Add like terms

First, let find the vertex.

Plug this in to find the minimum point.

So the minimum point is at (3,49).

Now we can find some zeroes.

Apply AC Method.

Solve each equation for zero.

So Graph points

(3,49)

(-4,0)

(10,0)

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0