subject
Mathematics, 10.06.2021 17:00 nani97

Solve the following equation algebraically: Negative 16 = 16 x squared How many solutions does this equation have? Explain. a. Negative 1 = x squared; One solution because only -1 will satisfy the equation. b. Negative 1 = x squared; No real solution because there is no real number that, when squared, produces -1. c. 1 = x squared; Two solutions because the square root of 1 is positive 1 and negative 1. d. 1 = negative x squared; One solution because only -1 will satisfy the equation. Please select the best answer from the choices provided A B C D

ansver
Answers: 3

Another question on Mathematics

question
Mathematics, 21.06.2019 14:40
Someone . me. compound probability
Answers: 2
question
Mathematics, 21.06.2019 16:30
What is true about the dilation? it is a reduction with a scale factor between 0 and 1. it is a reduction with a scale factor greater than 1. it is an enlargement with a scale factor between 0 and 1. it is an enlargement with a scale factor greater than 1.
Answers: 2
question
Mathematics, 21.06.2019 19:30
The measure of an angle is 117°. what is the measure of a supplementary angle?
Answers: 2
question
Mathematics, 21.06.2019 22:00
Rewrite 9 log, x2 in a form that does not use exponents. 9log, x = log, x
Answers: 3
You know the right answer?
Solve the following equation algebraically: Negative 16 = 16 x squared How many solutions does this...
Questions
question
Biology, 28.08.2019 10:30