How many and what type of solutions does 7x^2−4x+3 have? 1 rational solution 2 rational solutions 2 irrational solutions 2 nonreal solutions

Step-by-step explanation:

7x^2-4x+3=0

a=7

b=-4

c=3

Solution given:

7x²-4x+3=0

taking common 7

7(x²+4/7*x+3/7)=0

x²+2*x*2/7+(2/7)²-(2/7)²+3/7=0

(x+2/7)²=-17/49

x+2/7=

x=±√(17)/7-2/7

taking positive

x=√(17)/7-2/7

x=0.39

taking positive

x=-√(17)/7-2/7

x=-0.87

2:unreal number

2

step-by-step explanation:

answer: i believe the answer is e

step-by-step explanation: