You are in charge of monitoring the pressure of a compressed air tank in a processing plant. After repeating the pressure measurement a large number of times, you found that the pressure values have Gaussian distribution with a mean value of 69 psi and a standard deviation of 10 psi. If it is important that the pressure stays below 84 psi, what is the probability (in percent) that the pressure will exceed this value

11.5

Step-by-step explanation:

Given that :

I am in charge of the pressure reading in a compressed air tank of a processing plant.

The Gaussian distribution having a mean value = 69 psi

Standard deviation = 10 psi

Here we have to find the probability that the pressure will exceed 84 psi.

So,

                   = 0.115

                   = 11.5

this is false ^.^ lol

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;