If A is a 3×3 singular matrix such that λ1=1−i is an eigenvalue of A, then the other eigenvalues of A are 0,1+i

1 + i

Step-by-step explanation:

Given that A is a 3 * 3 singular matrix

one of its eigenvalue ( λ1 ) = 1 - i

Given that the determinant of a singular matrix is = 0

therefore the second eigen value ( λ2 ) = 1 + i

1 - i + 1 + i  = 0

the answer is 0.3175 hope that you ^w^

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