Question 2 (6 points) (02.01 LC)
A DOG has coordinates D (3, 2), O (2,-4) and G (-1,-1). A translation maps point D to D' (2, 4). Find the coordinates of O' and G under this
translation. (6 points)
O'(-1, 1); GP (1,-2)
Ob
O' (3, 0); G (-1,-1)
Ос
O'(0, -3); G (-3,0)
Od
O' (1.-2); G (-2, 1)

it is c, trust i got your back lol

step-by-step explanation:

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation:

answer: (3,11) is your answer.