In \triangle JKL,△JKL, \overline{KL}\cong \overline{JK} KL ≅ JK and \text{m}\angle J = 17^{\circ}.M∠J=17 ∘ . Find \text{m}\angle K. M∠K.

m<K =

Step-by-step explanation:

With the given conditions in the question, it would be observed that ΔJKL is an isosceles, since KL ≅ JK. So that JL is the base of the triangle:

m<J ≅ m<L = (base angle of an isosceles triangle are equal)

Then;

m<J + m<K + m<L = (sum of angles in a triangle)

+ m<K + =

m<K + 34 =

m<K  = - 34

m<K =

Thus, with respect to the given question, the measure of angle K is . Which is an obtuse angle of the triangle JKL.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !