Consider the vector space P 3 (t) of polynomials of legree <= 3 Show that S=\ (t-1)^ 3 ,(t-1)^ 2 ,1\ is a basis of P 3 (t) or not.​

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step-by-step explanation:

add the table and i will answer correctly

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

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