By what percent will a fraction increase if its numerator is decreased by 60% and its denominator is decreased by 20%?

9514 1404 393

  -50%

Step-by-step explanation:

Suppose the fraction is f = p/q before any changes.

Decreasing the numerator by 60% multiplies it by (1 -0.60) = 0.4.

Decreasing the denominator by 20% multiplies it by (1 -0.20) = 0.8.

Then the new fraction is ...

  f' = p(0.4)/(q(0.8)) = (p/q)(0.4/0.8) = f(0.5) = f(1 -0.50) = f(1 +(-50%))

The increase in the value of the fraction is -50%.

if x decreases by 4 then y increases by 10

step-by-step explanation:

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8