Solve for x. Round to the nearest tenth of a degree, if necessary PLEASE HELP I HAVE 10 MINS TILL ITS DUE

x = 47.4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta  = adj / hyp

cos x = 8.8 / 13

Take the inverse cos of each side

cos ^-1 ( cos x) = cos ^-1( 8.8 /13)

x = cos ^-1( 8.8 /13)

x =47.39633319

Rounding to the nearest tenth

x =47.4

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: