Solve the system of equations. y = 2x
y = x2-8
O A. (2, 4) and (-4,-8)
O B. (-2,-4) and (-4,-8)
O C. (2, 4) and (4,8)
O D. (-2,-4) and (4,8)​

D

Step-by-step explanation:     Time Stamp (6  9  10  32)

Easiest way is to graph both equation and look for the intersections  see attached sreen shot

or  solve by substitution

y = 2x

y = x²- 8

2x = x²- 8                  solve for x

0  = x² - 2x - 8          factor

0 = (x - 4)(x + 2)

0 = 0   when x = 4 and -2      

calculate the y values

y = 2x      x = 4

y = 8                              (4, 8)

y = 2x      x = -2

y = -4                            (-2, -4)

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.