A sample proportion of 0.36 is found. To determine the margin of error for this statistic, a simulation of 100 trials is run, each with a sample size of 50 and a point estimate of 0.36. The minimum sample proportion from the simulation is 0.28, and the maximum sample proportion from the simulation is 0.40.

The margin of error of the population proportion is found using half the range.

What is the interval estimate of the true population proportion?

(0.30,0.42)

(0.20,0.52)

(0.24,0.48)

(0.22,0.50)

(0.30, 0.42)

Step-by-step explanation:

Given the sample proportion is = 0.36

Number of trials required for determining the margin of the error = 100

Sample size, n = 50

The point estimate = 0.36

The minimum sample proportion form the simulation = 0.28

The maximum sample proportion from the simulation = 0.40

Also the margin of the error of population proportion is found by using the half of the range.

Therefore, the interval estimate for the true population proportion is = (0.30, 0.42)

too hard the other guy did it

step-by-step explanation:

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step-by-step explanation:

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