Consider the function defined by F(x, y) = xy(2x^2 + 6y^2)/x^2 + y^2
except at (x, y) = (0, 0) where F(0, 0) = 0. Then we have
partial differential/partial differential y partial differential F/partial differential z (0, 0) =
partial differential/partial differential z partial differential F/partial differential y (0, 0) =
Note that the answers are different. The existence and continuity of all second partials in a region around a point guarantees the equality of the two mixed second derivatives at the point. In the above case, continuity fails at (0,0).

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

so, converting firstly the mixed fractions to improper fractions and then "adding".

a

step-by-step explanation:

110

step-by-step explanation:

based on the question i am guessing that it is a typo for abc