Write an exponential function in the form y=ab^x that goes through the point (0,17) and (6,1088)

y = 17(2)^x

Step-by-step explanation:

If the graph of y = ab^x goes through (0, 17), then

                        17 = ab*0, or a = 17

Then the function is y = ab^x with a = 17, or

                                  y = 17*b^x and we must find b.

If the graph of y = 17*b^x also goes through (6, 1088), then the following must be true:   1088 = 17*b^6

which reduces to 64 = b^6

Taking the sixth root of both sides, we get 64^(1/6) = b, and so b = 2

Then the desired exponential function is

y = 17(2)^x

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2