Solve:
ab^2-(a-c)b-c=?

ab^2-(a-c)b-c

ab^2-ab+bc-c

ab(b-1)+c(b-1)

(b-1)(ab+c)

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

to have more of what you want like money

step-by-step explanation:

save it by not spending on unnecessary stuff and have more