Two containers, A and B begin with equal volumes of liquid. 120 ml is then poured from A to B.
А
B
Container B now contains 4 times as much liquid as A.
Find the volume of liquid left in container A at the end.
A
A
B.
B
Volume left in container A=
20
ml

volume left in A is 80ml

Step-by-step explanation:

let original volume in both be x ml

after pouring from A to B

vol in A = x - 120

vol in B = x + 120

now it is given that

vol in B = 4 times vol in A

implies

hence original volume in A is 200ml. after pouring in B it is 200-120 = 80 ml

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3