Given that cot(θ)= -√5/3 and cos(θ) < 0, find sin(θ)

D. 3√14 /14

Step-by-step explanation:

given that cot(θ)= -√5/3 and cos(θ) < 0

cot(θ)= -√5/3 and cos(θ) < 0, the angle should be on quadrant II.

cot(θ)= -√5/3 => x = -√5 , y = 3

h = √(-3)²+5 =√14

so, sin(θ) = y/h = 3/√14 = 3√14 /14

  about 5.6 days

step-by-step explanation:

we can fill the given information into the decay equation and solve for the value of t at which half the sample remains.

the half-life is about 5.6 days.

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

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step-by-step explanation: