4ab (a -b) + b (2b -2a²) for a = 1 and b= -1
simplify it

Step-by-step explanation:

4ab(a-b)+b(2b-2a^2)

=4*1*-1[1-(-1)]+(-1){2(-1)-2*1^2}

=-4(1+1)-1{-2-2}

=-4*2-1(-4)

=-8+4

=-4

by my calculations the answer is 10

Step-by-step explanation:

4×1(1-1)+1(2×1-4)

4+1(2-4)

5×2

10

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: